Algebra Practice

Algebra Word Problems Practice Test

Build and solve equations from rates, mixtures, geometry, percentages, work, growth, and everyday models.

Algebra Word Problems Practice Test

20 varied algebra word problems with equations and worked explanations.

Instant feedback · Worked explanations
Applied Algebra Storyboard

Word problems become algebra when every sentence is turned into a relationship with units.

Applied algebra is less about choosing a formula from memory and more about deciding what the quantities mean. Define the unknown, attach units, translate each sentence into a relationship, and then choose the model family: linear, system, quadratic, rational rate, proportion, or exponential. The final number is not complete until it makes sense in the original situation.

Fixed & variable costDistance-rate-timePerimeter & areaPercent changeDilutionConsecutive integersTicket systemsBoat & currentCombined workAgesGrowthAveragesCatch-upCommissionRight triangles

1. Fixed and variable costs belong in different parts of the model

A fixed charge is present even when usage is zero; the variable part changes with the number of units.

Build the model

C=F+rx
46=10+6r
r=6

The variable rate is found only after the fixed charge is separated.

Commission uses the same structure

C=500+0.08s
900=500+0.08s
s=5000

The commission applies to sales, not to the entire paycheck.

2. Distance problems are easier when the three quantities are kept visibly separate

Distance equals rate multiplied by time. The route diagram helps keep the meaning of each quantity clear.

startfinishdistance traveledrate × time

Distance-rate-time model

d=rt
180=r·3
r=60

The rate has distance-per-time units, while the product of rate and time has distance units.

3. Catch-up and current problems change the effective rate

In catch-up problems, travelers may have different start times. In current problems, the current adds to or subtracts from the boat’s still-water speed.

Catch-up equation

d=60t
d=45(t+1)
60t=45(t+1)
t=3

Equal distance, not equal time, creates the meeting condition.

Boat and current

30=(r+2)·2
r=13
r2
11

Downstream and upstream speeds differ because the current changes the effective rate.

4. Geometry word problems begin by choosing the correct measurement formula

Perimeter adds side lengths; area multiplies dimensions. A negative dimension from a quadratic must be rejected.

Perimeter

2x+2(x+4)=28
x=5

The total distance around the boundary is a linear expression in the side length.

Area

A=x(x+3)
x2+3x=40
(x5)(x+8)=0
x=5

Only the positive dimension is meaningful in the geometric context.

5. Percent and mixture problems depend on applying rates to the correct base

A percent increase multiplies the original amount. A mixture equation balances the amount of pure substance.

Percent increase

C=80(1+0.15)
C=92

The percent is applied to the original base amount, not to the final total.

Dilution and concentration

8·0.25+x·0.50=(8+x)·0.35
2+0.50x=2.8+0.35x
x=0.80.15
x=163

The concentration multiplies the quantity of each mixture before the pure amounts are combined.

6. A mixture diagram helps separate amount from concentration

The volume and the percent concentration are different quantities; the equation combines them through the amount of pure substance.

first mixturefinal mixturelower concentrationtarget concentration

Read the diagram before writing the equation

The first container contributes one amount of pure substance, the added mixture contributes another, and the final container must match the target concentration. This is why the model multiplies quantity by concentration instead of adding percentages directly.

7. Some stories need a system, while others need reciprocal work rates

Ticket counts and ticket revenue create two simultaneous equations. Combined work adds rates, not times.

Ticket revenue system

a+c=120
12a+8c=1200
4a=240
a=60
c=60

One equation tracks quantity; the other tracks money.

Combined work

16+18=1t
724=1t
t=247

Workers contribute fractions of one job per unit time, so their rates add.

8. Ages, averages, and consecutive integers are translation problems

The algebra is usually linear, but the hard part is preserving the relationships stated in words.

Age relationship

x+(x+12)=52
x=20
x+12=32

The older age is defined relative to the younger age.

Average

72+84+x3=80
156+x=240
x=84

Average equals total divided by count.

Consecutive integers

x+(x+1)+(x+2)=75
x=24
24,25,26

Each next integer is one larger than the previous one.

9. Compound growth uses repeated multiplication rather than repeated addition

The growth factor is raised to the number of periods.

Model
P=1200(1+0.05)n

The starting amount is multiplied by a growth factor each period.

Substitute the number of periods
P=12001.053
Interpret the result
P1389.15

The final amount should be larger than the starting amount for positive growth.

10. Right-triangle stories become quadratic equations through the Pythagorean relationship

The diagram helps keep the two legs and the hypotenuse in the correct positions before squaring.

one legother leghypotenuse

Translate the side relationship

x2+(x+3)2=152
2x2+6x216=0
(x9)(x+12)=0
x=9

The negative algebraic root is rejected because a physical side length cannot be negative.

11. Proportions model equal ratios

Cross multiplication clears the denominators, but the interpretation still comes from the original ratio statement.

Set up the proportion

x12=1520
20x=180
x=9

Check the units

Both ratios should compare the same kinds of quantities in the same order. Reversing only one ratio changes the model.

12. Common word-problem mistakes usually come from modeling the wrong relationship

The arithmetic may be correct even when the model is wrong, so the final reasonableness check matters.

Rate mixed with time

Distance uses rate multiplied by time; the two quantities are not interchangeable.

Percent applied to the wrong base

Percent change is measured from the original amount unless the problem explicitly says otherwise.

Work times added directly

Combined work adds job-per-time rates, not completion times.

Negative geometry root accepted

Algebraic roots still have to satisfy physical dimension conditions.

Age relationship reversed

Define the younger and older quantities before translating the sentence.

Fixed charge forgotten

A starting amount or fixed fee belongs in the model even when the variable usage is zero.

Final word-problem audit

Before accepting an answer, confirm the unknown, units, model family, equation structure, and whether the result is reasonable in context.

1
What does the variable represent?Name it and attach units before writing the equation.
2
What relationship does each sentence describe?Translate first; calculate second.
3
What model family fits the story?Choose linear, system, rate, quadratic, proportion, or exponential structure.
4
Are rates, times, percentages, and fixed terms attached to the correct quantities?Unit logic catches many setup errors.
5
Does the algebra produce multiple candidates?Reject impossible ages, lengths, times, or other context-invalid values.
6
Is the final number reasonable?Compare its sign, size, and units with the original story.
This block supports the Algebra Word Problems Practice Test. Its examples are illustrative rather than copies of the test questions. The focus is fixed and variable costs, distance-rate-time, catch-up motion, current and boat speed, perimeter, area, percent change, dilution, ticket-revenue systems, combined work, age relationships, compound growth, averages, consecutive integers, commissions, proportions, mixtures, and right-triangle models.