Algebra Practice

Solving Quadratics by Factoring Practice Test

Factor quadratics completely, apply the zero-product property, and solve every factor equation.

Solving Quadratics by Factoring Practice Test

This test has 20 questions

Instant feedback · Worked explanations

After the test · factor-to-root workshop

Factoring solves a quadratic only when every factor is carried all the way to a root equation

This practice set focuses on solving rather than merely recognizing a factorization. The equation may be monic or nonmonic, may contain a greatest common factor, may hide a difference of squares, may produce a repeated root, or may need to be moved to standard zero form before any factoring begins. The finish line is not the factored expression — it is the complete set of solutions.

zero-product propertyGCFtrinomials difference of squaresrepeated rootsnonmonic quadratics
The page's four core actions are: move everything to zero, factor completely, set every factor equal to zero, and solve every resulting equation.

Master solving route

Use the same four-stage pipeline for every factorable quadratic

Zero form Move all terms to one side.

Factoring methods work cleanly when the equation is written as expression = 0.

Factor Factor completely, including any GCF.

Do not skip a common factor just because the remaining trinomial also factors.

Split Set every factor equal to zero.

This is the zero-product property.

Solve Solve every factor equation.

Collect all distinct roots, including x = 0 when x is a factor.

Quick factoring shelf

Core patterns for the skills named on this page

Zero-product property Product equals zero AB = 0 → A = 0 or B = 0

Each factor is a separate route to a root.

Greatest common factor Pull out the common factor first ax² + bx = x(ax + b)

If x is factored out, x = 0 is one possible root.

Difference of squares Special factoring identity a² − b² = (a − b)(a + b)

This pattern produces two linear factors immediately.

Repeated factor One distinct root (x − r)² = 0 → x = r

The factor appears twice, but the solution value is the same.

Monic trinomial x² + bx + c (x + m)(x + n), where m + n = b and mn = c

Look for two numbers with the needed sum and product.

Nonmonic trinomial ax² + bx + c, with a ≠ 1 (px + q)(rx + s)

The leading coefficients and constant factors must multiply correctly while the middle terms combine to b.

Visual factor tree

A factored quadratic branches into separate root equations

Factored equation (x − 4)(x + 2) = 0
= 0
Two factor equations x − 4 = 0
x + 2 = 0
x = 4 x = −2
GCF first · one of the page's explicit key ideas
START
3x² − 12x = 0 Both terms contain 3x.
FACTOR GCF
3x(x − 4) = 0 The common factor is part of the complete factorization.
ZERO PRODUCT
3x = 0 or x − 4 = 0 Every factor must be considered.
SOLUTIONS
x = 0 or x = 4 Ignoring the x-factor would lose a valid solution.

Move to zero first

A factorization is useful for solving only after one side of the equation is zero

Not ready to factor for roots

x² + 5x = 14

The zero-product property cannot yet be applied.

MOVE
14
LEFT

Standard zero form

x² + 5x − 14 = 0
(x + 7)(x − 2) = 0

Now each factor can be set equal to zero.

Monic versus nonmonic trinomials

The leading coefficient changes the factoring search, but the solving stage stays the same

Monic

x² + 7x + 12 = 0
(x + 3)(x + 4) = 0

Find two numbers that add to 7 and multiply to 12, then solve both factor equations.

Nonmonic

2x² + 7x + 3 = 0
(2x + 1)(x + 3) = 0

The leading coefficient must be distributed across the factors while the middle terms still combine correctly.

Difference of squares

Recognize the special pattern before searching for general trinomial factors

Pattern

x² − 25 = 0

Both terms are perfect squares and they are separated by subtraction.

Factor and solve

(x − 5)(x + 5) = 0
x = 5 or x = −5

The identity a² − b² = (a − b)(a + b) gives the factors immediately.

Repeated roots

A repeated factor creates one distinct solution value

Perfect-square factorization

x² − 6x + 9 = 0
(x − 3)² = 0

The same linear factor occurs twice.

SAME ROOT
TWICE

Distinct solution set

x − 3 = 0
x = 3

The multiplicity is 2, but there is only one distinct root.

Do not stop at the factorization

The solving stage must continue until every factor equation has been solved

This is the central emphasis of the page: factoring is a tool for producing simpler equations. The final response must be the roots, not merely a correct product of factors.

Factorization

(x − 2)(x + 6) = 0 is not yet the finished answer.

Factor equations

x − 2 = 0 and x + 6 = 0.

Solutions

x = 2 and x = −6.

Common mistakes from the page

Most errors come from stopping one step too early or dropping one factor

Not moved to zero
Trying to use zero-product reasoning while the equation still has a nonzero right side. First rewrite the equation as expression = 0.

The zero-product property requires a product equal to zero.

GCF ignored
Factoring only the trinomial part while leaving a common factor untreated. Factor completely, including the GCF.

The common factor may itself generate a valid root.

Stop at factors
(x − 4)(x + 2) = 0 submitted as the final answer. Continue to x = 4 and x = −2.

The page explicitly focuses on solving rather than merely identifying a factorization.

x = 0 omitted
x(x − 7) = 0 reported only as x = 7. x = 0 or x = 7.

Every factor must be set equal to zero.

Repeated root doubled
(x − 3)² = 0 reported as two different solutions. There is one distinct solution, x = 3.

The factor has multiplicity two, but the value is the same.

Final factoring checklist

Before selecting an answer, verify the entire factor-to-root chain

Zero form All terms are on one side and the other side is exactly zero.
Complete factorization Any GCF, trinomial structure, or difference-of-squares pattern has been fully factored.
Every factor used Each factor is set equal to zero, including an isolated x-factor.
Distinct roots reported Every factor equation is solved, with repeated factors recognized as one distinct solution.