Synthetic Division Practice Test
This test has 20 questions
Practice quotient, remainder, factor, and parameter problems with synthetic division.
This test has 20 questions
Synthetic division replaces polynomial symbols with an organized coefficient row, but it works only when the setup is exact. The synthetic number comes from solving the divisor equal to zero, missing powers require zero placeholders, and the final bottom entry has a special role: it is the remainder.
The method becomes compact because the variable powers are implied by position. That makes setup discipline more important: one wrong synthetic value or one missing zero coefficient shifts the entire calculation.
Use the root of the linear divisor, not the printed sign by itself.
Each coefficient slot represents one descending power, so missing powers must still receive a zero.
All but the final bottom entry become quotient coefficients; the final entry is the remainder.
The sign printed in the divisor can be misleading if read mechanically. Rewrite the divisor in the form , then use .
Read the divisor as an equation and solve it equal to zero.
Because synthetic division hides the variable symbols, coefficient position carries all the exponent information. If one power is missing, a zero coefficient must mark its slot.
Unlike polynomial long division, synthetic division compresses each cycle to arithmetic on coefficients. The pattern repeats from left to right until the final column is reached.
The leading coefficient becomes the first quotient coefficient.
Take the newest bottom entry and multiply it by the synthetic number.
The sum becomes the next bottom entry, and the cycle repeats.
The bottom row has two jobs. Every entry except the last describes the quotient; the final entry is the remainder.
The first three values are quotient coefficients. The final value is the remainder.
If a cubic dividend is divided by a linear divisor, the quotient is quadratic. Thus the quotient row , , becomes .
Synthetic division connects directly to the Factor Theorem. A zero final entry means zero remainder, so the divisor is an exact factor of the dividend.
If a coefficient contains an unknown parameter, the synthetic process may produce a final entry involving that parameter. A condition such as “the divisor is a factor” then gives an equation to solve.
If the last synthetic entry is and the divisor is known to be a factor, set . Therefore .
If the remainder is specified as , set the final synthetic expression equal to rather than zero.
A correct synthetic quotient and remainder must satisfy the polynomial division identity. This is the strongest way to catch a shifted coefficient row or a wrong synthetic sign.
Most wrong answers can be traced to one of two setup errors: using the wrong synthetic value or omitting a zero coefficient. The remaining mistakes usually occur when interpreting the bottom row.
For , the synthetic value is , not .
Skipping a zero coefficient shifts every later position and changes the quotient.
The leading coefficient drops directly before any multiplication begins.
Every product uses the same synthetic number determined from the divisor.
The final bottom entry is the remainder, not another quotient coefficient.
A final zero is not merely arithmetic; it confirms that the divisor is a factor.
These examples are illustrative teaching examples, not questions copied from the test.
Divisor uses synthetic value .
Divisor uses synthetic value .
must include the zero cubic coefficient.
If the final bottom entry is , the remainder is .
If the final entry is , the divisor is a factor of the dividend.
If the final entry is and the divisor must be a factor, solve .
Before accepting a quotient or factor conclusion, audit the synthetic value, coefficient positions, and interpretation of the last entry.